Question

$('#customerAddress').text().replace(/\xA0/,"").replace(/\s+/," ");

Going after the value in a span (id=customerAddress) and I’d like to reduce all sections of whitespace to a single whitespace. The /\s+/ whould work except this app gets some character 160’s between street address and state/zip
What is a better way to write this? this does not currently work.

UPDATE:
I have figured out that

$('.customerAddress').text().replace(/\s+/g," ");

clears the 160s and the spaces.
But how would I write a regex to just go after the 160s?

$('.customerAddress').text().replace(String.fromCharCode(160)," ");

didn’t even work.

Note: I’m testing in Firefox / Firebug

Answer 1

\s does already contain the character U+00A0:

[\t\n\v\f\r \u00a0\u2000\u2001\u2002\u2003\u2004\u2005\u2006\u2007\u2008\u2009\u200a\u200b\u2028\u2029\u3000]

But you should add the g modifier to replace globally:

$('#customerAddress').text().replace(/\s+/g, " ")

Otherwise only the first match will be replaced.