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Home/ Questions/Q 6843927
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:18:45+00:00 2026-05-27T00:18:45+00:00

D2.056 void f(string[] names…) { foreach (name; names) { mixin(string ~ name ~ =

  • 0

D2.056

void f(string[] names...)
{
    foreach (name; names)
    {
        mixin("string " ~ name ~ " = name;");
    }
}

int main()
{
    f("a", "b");
    return 0;
}

Why does this not work? It complains about ‘name’ not being compile-time readable, but that is a false statement. The content of ‘names’ is known at compile-time, since it is {“a”, “b”};

I am trying to make a bind with a library, and the passed function names must be defined and pointed to the library.

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:18:46+00:00Added an answer on May 27, 2026 at 12:18 am

    Functions must be valid for both compilation and compile-time execution. Obviously f is not compilable.

    Depending on what you’re trying to achieve, you could either make names a template argument (which would make the foreach static), or make f build a string and mixin the result at f‘s call site.

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