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Home/ Questions/Q 8558237
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T15:45:58+00:00 2026-06-11T15:45:58+00:00

data.d = [ { NodeId: BK01, NodeName: Books, ParentId: null, Likes: null }, {

  • 0

data.d =

[
  {
    "NodeId": "BK01",
    "NodeName": "Books",
    "ParentId": null,
    "Likes": null
  },
  {
    "NodeId": "CO01",
    "NodeName": "Computers",
    "ParentId": null,
    "Likes": null
  },
  {
    "NodeId": "GA01",
    "NodeName": "Gaming",
    "ParentId": null,
    "Likes": null
  },
  {
    "NodeId": "MO01",
    "NodeName": "Mobile & Accessories",
    "ParentId": null,
    "Likes": null
  }
]

WebService

 <WebMethod()> _
    Public Shared Function getCategories() As String
        Dim details As New List(Of Nodes)()
        Dim index As New Default2
        Using ds As Data.DataSet = index.db.ExecuteDataSet(CommandType.Text, "SELECT NodeID,NodeName FROM Nodes WHERE ParentID='1'")
            Dim JaggedArray As String()() = New String(ds.Tables(0).Rows.Count - 1)() {}
            Dim i As Integer = 0
            For Each rs As DataRow In ds.Tables(0).Rows
                Dim node As New Nodes()
                node.NodeId = rs("NodeId").ToString
                node.NodeName = rs("NodeName").ToString
                details.Add(node)
                'JaggedArray(i) = New String() {rs("NodeName").ToString(), rs("NodeID").ToString()}
                i = i + 1
            Next
        End Using
        Dim js As New JavaScriptSerializer()
        Dim strJSON As String = js.Serialize(details.ToArray)
        Return strJSON

    End Function

AJAX Call

<script src="js/jquery-1.7.1.min.js" type="text/javascript"></script>
<script type="text/javascript">
    $(document).ready(function() {
        //alert("!!!");
        $.ajax({
            type: "POST",
            contentType: "application/json; charset=utf-8",
            url: "Default2.aspx/getCategories",
            data: "{}",
            dataType: "json",
            success: function(data) {
                var nodes = eval(data);
                alert(data.NodeName);
                $('#output').text(data.d);
                $.each(data.d, function(index, node) {
                $('#output').append('<p><strong>' + node.NodeName + ' ' +
                            node.NodeID + '</strong><br /> ');
                });
            },
            error: function(result) {
                alert("Error");
            }
        });
    });
</script>

How to loop through data.d to get the values? data.d.length gives me 219 but it should be 4 ? What am i doing wrong??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T15:46:00+00:00Added an answer on June 11, 2026 at 3:46 pm

    you can use $.map for E.G.

    $(document).ready(function () {
        $.ajax({
            type: "POST",
            url: "/--service--",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            async: false,
            success: function (data) {
                $.map(data.d, function (item) {
                    $("#name").append('<option value=' + item.ID+ '>' + item.Name + '</option>');
                });
            }
        });
    });
    
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