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Home/ Questions/Q 673621
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:36:58+00:00 2026-05-14T00:36:58+00:00

Database setup (MySQL) table: top_fives id, uid, first, second, third, fourth, fifth, creation_date 1,

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Database setup (MySQL)

table: top_fives

id, uid, first,     second, third,   fourth, fifth,   creation_date
1,  1,   cheese,    eggs,   ham,     bacon,  ketchup, 2010-03-17
2,  2,   mayonaise, cheese, ketchup, eggs,   bacon,   2010-03-17

Users can submit their top 5 of a certain subject. Now I would like a summary of the top fives ordered by popularity.

Each column has it’s own point value. column ‘first’ is rewarded 5 points, ‘second’ four points, ‘third’ three points, and so on…

So, in my example it should be something like this:

1 Cheese     (9 points = 5 + 4 -> 1 time in 'first' column and 1 time in 'second' column) 
2 Eggs       (6 points) 
3 Mayonaise  (5 points) 
4 Ketchup    (4 points) 
5 Bacon      (3 points) 
6 Ham        (3 points)

What would be the easiest solution (PHP) for this kind of situation?

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:36:58+00:00Added an answer on May 14, 2026 at 12:36 am

    The best solution would be to have normalized your data in the first place. And the only practical solution is to simulate the behaviour of a properly normalized database. Certainly the solution should not involve any PHP code and should be done on the database:

    SELECT type, SUM(score)
    FROM
    (
    (SELECT first as type, COUNT(*)*5 as score
     FROM top_fives
     GROUP BY first
    ) UNION
    (SELECT second AS type, COUNT(*)*4 as score
     FROM top_fives
     GROUP BY second
    ) UNION
    (SELECT third AS type, COUNT(*)*3 as score
     FROM top_fives
     GROUP BY third
    ) UNION
    (SELECT fourth AS type, COUNT(*)*2 as score
     FROM top_fives
     GROUP BY fourth
    ) UNION
    (SELECT fifith AS type, COUNT(*) as score
     FROM top_fives
     GROUP BY fifth
    ) 
    )
    GROUP By type
    ORDER BY SUM(score) DESC;
    

    C.

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