Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6255599
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T14:23:40+00:00 2026-05-24T14:23:40+00:00

Date column is created using colmodel below. This column shows values like 0101.0101.7070 for

  • 0

Date column is created using colmodel below.
This column shows values like 0101.0101.7070 for every date column.
if formatter:date is removed, date is correct.

How to show normal date values with formatter:date ?

{ "name":"Date",
"formatter":"date",
"datefmt":"dd.mm.yyyy",
"formatoptions":{"newformat":"dd.mm.yyyy"},
"editable":true
}

Update.

Data is passed from server using json in same dd.mm.yyyy format like

{"total":2,"page":1,"records":57,"rows":
[{"id":"9279","cell":["9279","42","","10.08.2011","","","","False"]},
 {"id":"9278","cell":["9278","41","","12.08.2011","","","","False"]},

…

Using d.m.y formats in column options as suggested shows proper dates but with 2 year digits only..
I’m looking for a 4-digit year numbers. I tried d.m.yyyy format but this shows 8 digit year numbers and 1 for month and day as 01.01.70707070

I also tried to add srcformat: ‘dd.mm.yyyy’ to formatoptions but this does not change the wrong result.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T14:23:42+00:00Added an answer on May 24, 2026 at 2:23 pm

    To display the day as the number you should use j or d. For the displaying month as the number you should use n or m. The d and m includes 0 padding at the beginning if needed. The ‘y’ means two digit year format and Y means four digit year.

    So you probably need srcformat: 'd.m.Y' or srcformat: 'j.n.Y'.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

How do you implement a last-modified column in SQL? I know for a date-created
Using Access 2003 Date Column datatype is text Table1 Date 20090528 20090529 20090530 20090502
With a table created using this SQL Create Table X ( ID varchar(4) Not
I am looking for a formatted date field using Created. So I created a
I've created list(containing name,mail,number,date) from server using listview extending by listactivity. And, i've also
I've created a simple DB using SQLAlchemy in python and there is a column
I am using Spring HibernateTemplate, OpenSessionInViewFilter(actually I extended this class and created my own
We are using WSS 3 SP2. I'd like to preface this by saying that
I have a table which will have a date/time column to store create date
@Column(name=DateOfBirth) private Date dateOfBirth; I specifically need the above code to create a column

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.