Question

DB TABLE

select * from AAA;
id   |    Name     |    Class  | Grade    |
--------------------------------------
1    |     john    |      1    |   A      |
2    |     Jane    |      2    |   B      |
3    |     Joon    |      2    |   A      |
4    |     Josh    |      3    |   C      |

|

Code

Django
search_result = AAA.objects.filter(Grade = 'B').count() 
print search_result 

search_result -> 2

I want to change Grade to Class by VALUE.

Django
target_filter = 'Class'
search_result = AAA.objects.filter(__"target_filter..."__ = '3').count()

search_result -> 1

Q) How can I complete this code? Is it possible?

Answer 1

you can shorten aeby’s example by putting the kwargs in directly

target_filter = 'Class'
search_result = AAA.objects.filter(**{target_filter:3}).count()