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Editorial Team
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Asked: 2026-05-18T09:23:06+00:00

def a(b=[]): b.append(1) return b print a() print a() All of a sudden i

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def a(b=[]):
    b.append(1)
    return b

print a()
print a()

All of a sudden i got a list with 2 elems, but how? Shouldn’t b be getting set to empty list every time.

Thanks for the help

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1 Answer

  1. Editorial Team

    Nothing to do with closures, at least not in the usual sense.

    The default value for b is not “a new empty list”; it is “this particular object which I just created right now while defining the function, initializing it to be an empty list”. Every time the function is called without an argument, the same object is used.

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