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Home/ Questions/Q 520935
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:11:50+00:00 2026-05-13T08:11:50+00:00

def a(something): return something*something #Case I – referencing b = a #Case II –

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def a(something):
    return something*something

#Case I - referencing
b = a
#Case II - creating a new function to call the first
def b(something):
    return a(something)

Which is better style? Are there drawbacks to either?

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:11:50+00:00Added an answer on May 13, 2026 at 8:11 am

    b = a means calls to b will be faster (no overhead), but introspection (e.g. help(b)) will show the name a, and a‘s docstring. Unless the latter issues are a killer for your specific application (some kind of tutorial, for example), the speed advantage normally wins the case.

    Consider, e.g. in ref.py:

    def a(something):
        return something*something
    
    #Case I - referencing
    b1 = a
    #Case II - creating a new function to call the first
    def b2(something):
        return a(something)
    

    Now:

    $ python -mtimeit -s'import ref' 'ref.a(23)'
    1000000 loops, best of 3: 0.716 usec per loop
    $ python -mtimeit -s'import ref' 'ref.b1(23)'
    1000000 loops, best of 3: 0.702 usec per loop
    $ python -mtimeit -s'import ref' 'ref.b2(23)'
    1000000 loops, best of 3: 0.958 usec per loop
    

    I.e., calls to b1 (pure referencing) are just as fast as calls to a (actually appear 2% faster in this run, but that’s well within “the noise” of measurement;-), calls to b2 (entirely new function which internally calls a) incur a 20% overhead — not a killer, but normally something to avoid unless that performance sacrifice buys you something specific that’s quite important for your use case.

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