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Home/ Questions/Q 948075
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:11:07+00:00 2026-05-15T23:11:07+00:00

def do_work(): medications_subset2(b,[‘HYDROCODONE’,’MORPHINE’,’OXYCODONE’]) def medications_subset2(b,drugs_needed): MORPHINE=[‘ASTRAMORPH’,’AVINZA’,’CONTIN’,’DURAMORPH’,’INFUMORPH’, ‘KADIAN’,’MS CONTIN’,’MSER’,’MSIR’,’ORAMORPH’, ‘ORAMORPH SR’,’ROXANOL’,’ROXANOL 100′] print drugs_needed[1][0] how

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def do_work():
  medications_subset2(b,['HYDROCODONE','MORPHINE','OXYCODONE'])

def medications_subset2(b,drugs_needed):
  MORPHINE=['ASTRAMORPH','AVINZA','CONTIN','DURAMORPH','INFUMORPH',
            'KADIAN','MS CONTIN','MSER','MSIR','ORAMORPH',
            'ORAMORPH SR','ROXANOL','ROXANOL 100']
  print drugs_needed[1][0]

how do i print ASTRAMORPH (this is the first element in MORPHINE)

i NEED to make use of drugs_needed, since this is being passed in from do_work

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:11:07+00:00Added an answer on May 15, 2026 at 11:11 pm

    Can you define MORPHINE this way?

    drugs = {
      'MORPHINE': ['ASTRAMORPH',...],
      'HYDROCODONE': [...],
      ...
    }
    

    then you can refer to it by

    print ( drugs[drugs_needed[1]][0] )
    
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