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Home/ Questions/Q 645043
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:27:32+00:00 2026-05-13T21:27:32+00:00

def myFunc(arg1, arg2): print This is a test with + arg1 + and +

  • 0
def myFunc(arg1, arg2):
    print "This is a test with " + arg1 + " and " + arg2

while (input != "quit"):
    input = raw_input("> ")

    if input != "quit":
        eval(input)

This code gives me a prompt, allowing me to invoke myFunc with parameters I want. I know that eval can be dangerous if a dictionary is not supplied, so I added this:

eval(input, {"__builtins__": {} }

Now I can no longer invoke myFunc. How do I fix this without leaving eval open to exploits?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:27:32+00:00Added an answer on May 13, 2026 at 9:27 pm

    This will allow you to use myFunc:

    eval(input, {"__builtins__": {}, "myFunc": myFunc})
    

    However, as others have pointed out, using eval is inherently insecure, and still vulnerabe to exploits.

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