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Home/ Questions/Q 3360036
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T02:56:41+00:00 2026-05-18T02:56:41+00:00

def path(request, mypath): mypath = request.path_info _listdir = os.listdir(mypath) # [‘folder1’, ‘folder2’, ‘folder3’, ‘folder4’]

  • 0
def path(request, mypath):
    mypath = request.path_info
    _listdir = os.listdir(mypath)  # ['folder1', 'folder2', 'folder3', 'folder4']
    mess = _listdir
    a = ' '
    x=0
    scope = vars()  

    for i in mess:  
        scope['x']+=1  
        a += mess[x]
        a += '\n'

    return HttpResponse(a)

I hope the output is like this:

folder1
folder2
folder3
folder4

but why the output just like this:

folder1
folder1
folder1
folder1

any help?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T02:56:42+00:00Added an answer on May 18, 2026 at 2:56 am
    I hope the output is like this:
    
    folder1
    folder2
    folder3
    folder4
    

    Thus shall you have your output…

    for i in os.listdir(mypath):
        print i
    

    You can return the i in the loop with HttpResponse there should be no problem, do this

    returnString = ""
    for i in os.listdir(mypath):
        returnString = returnString + i + "\n"
    
    return returnString
    
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