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Home/ Questions/Q 8851989
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:17:29+00:00 2026-06-14T13:17:29+00:00

def test(x,theList): theList.append(x) if x < 2: x = x + 1 test(x,theList) print

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def test(x,theList): 
    theList.append(x) 
    if x < 2: 
        x = x + 1 
        test(x,theList) 
        print x 
        print theList 

test(1,[]) 

Why is the result [1,2]? And not only [1]?

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:17:30+00:00Added an answer on June 14, 2026 at 1:17 pm

    Because you execute the print statement after the recursive call to test() returns.

    Python objects are always passed by reference, so when the second invocation of test calls theList.append(x), it is appending to the original list that was passed in, which is what you then print.

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