Question

1. define a string
2. define string’s len
3. print true if the string len is even and the right half identical to the left half, else – print false.

I need to do it only in 3 lines and it has to work for every string len without change the condition in (3).

We didn’t learn or loop yet. It supposed to be with slice.

please help.

---

i tried to do it:

some_string = "bb" 
str_len = len (some_string),str(a)
if str_len%2==0 and some_string[0:a/2]==some_string[a/2:0]: print "True"
else: print "False"

but something went wrong

Answer 1

Your code is almost fine, just a little improvement needed. You don’t actually need to check for even length using modulus(%) operator, as the second condition will automatically take care of it.

So, Here’s how your code would look: –

>>> def check_str(value):
        mid = len(value) / 2
        return True if value[:mid] == value[mid:] else False

>>> check_str("abab")
True
>>> check_str("abb")
False
>>> check_str("aaba")
False