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Home/ Questions/Q 938151
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T21:35:43+00:00 2026-05-15T21:35:43+00:00

#define LINK_ENTITY_TO_CLASS(mapClassName,DLLClassName) \ static CEntityFactory<DLLClassName> mapClassName( #mapClassName ); This is a macro from the

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#define LINK_ENTITY_TO_CLASS(mapClassName,DLLClassName) \
    static CEntityFactory<DLLClassName> mapClassName( #mapClassName );

This is a macro from the Alien Swarm mod for Half-Life 2, meant to be compiled with MSVC.

I’ve never seen an argument preceded by a # in a macro before, and I’m not sure if this is a MSVC specific thing or just uncommon. What does it mean?

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  1. Editorial Team
    Editorial Team
    2026-05-15T21:35:44+00:00Added an answer on May 15, 2026 at 9:35 pm

    This is part of both standard C and C++ and is not implementation-specific. The # preprocessing operator stringizes its argument. It takes whatever tokens were passed into the macro for the parameter designated by its operand (in this case, the parameter mapClassName) and makes a string literal out of them. So, for a simple example,

    #define STRINGIZE(x) # x
    
    STRINGIZE(Hello World)
    // gets replaced with
    "Hello World"
    

    Note that the argument tokens are not macro replaced before they are stringized, so if Hello or World were defined as a macro, the result would still be the same. You need to use an extra level of indirection to get the arguments macro replaced (that linked answer discusses the concatenation operator, ##, but applies equally to the stringization operator.

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