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Asked: 2026-05-15T10:25:26+00:00

#define OUTGOING_MASK 0x0c #define OUTGOING_DISABLED 0x04 #define OUTGOING_ENABLED 0x08 #define OUTGOING_AUTO 0x00 #define REFER_SUPPORTED

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#define OUTGOING_MASK         0x0c
#define OUTGOING_DISABLED     0x04
#define OUTGOING_ENABLED      0x08
#define OUTGOING_AUTO         0x00
#define REFER_SUPPORTED       0x80

Assume support is some value of type int.
I have a getter function

int get()
{
if(OUTGOING_DISABLED == support & OUTGOING_MASK)
return 1;
else if(OUTGOING_ENABLED == support & OUTGOING_MASK)
return 2;
else if(OUTGOING_AUTO == support & OUTGOING_MASK)
return 3;
}

I need to write set function for this like

void set(int val)
{
if(val ==1)
//todo
else if(value == 2)
//todo
else if(value == 3)
//todo
}

How to write getter and setter functions for this?
I need to get/set the support variable here

REFER_SUPPORTED will always be set in support.

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1 Answer

  1. Editorial Team

    I have a statement such as a1 = b & a2; How to know the value of b using bitwise operators?

    You can’t recover value of b, unless a has ALL bits set. “&” is irreversible.

    Explanation. & operation has following table:

    a   b   result
1 & 1 = 1
0 & 1 = 0
1 & 0 = 0
0 & 0 = 0

    which means, to recover b, you could try to use following table:

    a   result  b
0   0       unknown - could be 1 or 0
0   1       invalid/impossible - could not happen
1   0       0
1   1       1

    As you can see it isn’t possible to guess b in all cases.

    In expression a & b = c, if you know c and a, you can’t recover b, because for every zeroed bit of c, and if corresponding bit of a is also zero, there are two possible states of corresponding bits of b. You can reliably recover b only if every bit of a is set to 1.

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