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Asked: 2026-06-12T09:07:23+00:00

#define START ((void (**)(int)) 0x0fff) *START = &fun_foo(); I haven’t seen this before. What

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#define START ((void (**)(int)) 0x0fff)

*START = &fun_foo();

I haven’t seen this before. What is happening here? Is void (**)(int) a function pointer?

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1 Answer

  1. Editorial Team

    void (**)(int) is a pointer to a pointer to a function that takes an int and returns nothing.

    So START is apointer to a function pointer, and *START is the actual function pointer which is set to point to fun_foo.

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