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Home/ Questions/Q 1035721
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:35:12+00:00 2026-05-16T14:35:12+00:00

Despite attempts to master grep and related GNU software, I haven’t come close to

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Despite attempts to master grep and related GNU software, I haven’t come close to mastering regular expressions. I do like them, but I find them a bit of an eyesore all the same.

I suppose this question isn’t difficult for some, but I’ve spent hours trying to figure out how to search through my favorite book for words greater than a certain length, and in the end, came up with some really ugly code:

twentyfours = [w for w in vocab if re.search('^........................$', w)]
twentyfives = [w for w in vocab if re.search('^.........................$', w)]
twentysixes = [w for w in vocab if re.search('^..........................$', w)]
twentysevens = [w for w in vocab if re.search('^...........................$', w)]
twentyeights = [w for w in vocab if re.search('^............................$', w)]

… a line for each length, all the way from a certain length to another one.

What I want instead is to be able to say ‘give me every word in vocab that’s greater than eight letters in length.’ How would I do that?

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:35:12+00:00Added an answer on May 16, 2026 at 2:35 pm

    You don’t need regex for this.

    result = [w for w in vocab if len(w) >= 8]
    

    but if regex must be used:

    rx = re.compile('^.{8,}$')
    #                  ^^^^ {8,} means 8 or more.
    result = [w for w in vocab if rx.match(w)]
    

    See http://www.regular-expressions.info/repeat.html for detail on the {a,b} syntax.

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