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Home/ Questions/Q 3669802
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T02:17:14+00:00 2026-05-19T02:17:14+00:00

dic1 = {‘a’:’a’,’b’:’c’,’c’:’d’} dic2 = {‘b’:’a’,’a’:’c’,’c’:’d’} dic1.keys() =>[‘a’, ‘b’, ‘c’] dic2.keys() =>[‘b’, ‘a’, ‘c’]

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dic1 = {'a':'a','b':'c','c':'d'}
dic2 = {'b':'a','a':'c','c':'d'}

dic1.keys()    =>['a', 'b', 'c']
dic2.keys()    =>['b', 'a', 'c']

dic1 and dic2 have the same keys, but in different order.

How to tell they have same keys(do not consider the order)?

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  1. Editorial Team
    Editorial Team
    2026-05-19T02:17:14+00:00Added an answer on May 19, 2026 at 2:17 am

    python 2.7

    dict views:
    Supports direct set operations, etc.

    >>> dic1 = {'a':'a','b':'c','c':'d'}
    >>> dic2 = {'b':'a','a':'c','c':'d'}
    >>> dic1.viewkeys() == dic2.viewkeys()
    True
    >>> dic1.viewkeys() - dic2.viewkeys()
    set([])
    >>> dic1.viewkeys() | dic2.viewkeys()
    set(['a', 'c', 'b'])
    

    similarly in 3.x: (thx @lennart)

    >>> dic1 = {'a':'a','b':'c','c':'d'}
    >>> dic2 = {'b':'a','a':'c','c':'d'}
    >>> dic1.keys() == dic2.keys()
    True
    >>> dic1.keys() - dic2
    set()
    >>> dic1.keys() | dic2
    {'a', 'c', 'b'}
    

    python 2.4+

    set operation: direct iteration over dict keys into a set

    >>> dic1 = {'a':'a','b':'c','c':'d'}
    >>> dic2 = {'b':'a','a':'c','c':'d'}
    >>> set(dic1) == set(dic2)
    True
    
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