Question

differencePercentage = Math.round(((Pay.init / Pay.current) * 100) – 100);

and that gives me the difference in percent between initial and current pay, but it’s reversed. When it’s positive i.e. pay is above the initial value it says -X%, and when it’s below it says X%.

Is there any obvious way I’m not seeing to polarize this?

Thanks for any insight. 🙂

Answer 1

differencePercentage = Math.round(100 - ((Pay.init / Pay.current) * 100));

[-(a – b) = -a + b = b – a]

Also:

differencePercentage = Math.round(100 * (1 - (Pay.init / Pay.current)));