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Home/ Questions/Q 7710529
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T01:08:55+00:00 2026-06-01T01:08:55+00:00

DirectoryInfo dir=new DirectoryInfo(path); if (!dir.Exists) { Directory.CreateDirectory(path); File.Create(path + \\file.xml); StreamWriter sw =new StreamWriter(path

  • 0
 DirectoryInfo dir=new DirectoryInfo(path);
 if (!dir.Exists)
  {
      Directory.CreateDirectory(path);
      File.Create(path + "\\file.xml");

      StreamWriter sw =new StreamWriter(path + "\\file.xml");
      sw.Flush();
      sw.Write("<?xml version='1.0' encoding='utf-8' ?><project></project>");
  }

error:

The process cannot access the file ‘C:\file.xml’ because it is being
used by another process.

why? How can close file?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T01:08:56+00:00Added an answer on June 1, 2026 at 1:08 am

    From MSDN

    The FileStream object created by this method (File.Create) has a default FileShare value of None; no other process or code can access the created file until the original file handle is closed.

    So the workaround is

      using(FileStream fs = File.Create(path + "\\file.xml"))
      {
           Byte[] info = new UTF8Encoding(true).GetBytes("<?xml version='1.0' encoding='utf-8' ?><project></project>");
           fs.Write(info, 0, info.Length);
      }
    

    EDIT: Changed removing the creation of the StreamWriter and using a FileStream
    However I don’t like this way as suggested by MSDN.
    StreamWriter has a constructor that can get a FileStream, but I thought that if we use

       using(StreamWriter sw = new StreamWriter(File.Create(path + "\\file.xml")))
       { 
          sw.Write("<?xml version='1.0' encoding='utf-8' ?><project></project>");
       }
    

    we get back the locking problem. However, I have tested and it works.
    Probably the StreamWriter constructor do some tricks on the FileStream returned by File.Create.

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