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Editorial Team
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Asked: 2026-05-25T06:09:32+00:00

Disclaimer: It’s been a while since I last wrote any code. The quality of

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Disclaimer: It’s been a while since I last wrote any code. The quality of my code is likely to be sub-par. You’ve been warned.

Greetings.

I am coding a basic form that uses a SELECT list I populate from my database.

However, my user needs the form to be dynamic and wants to be able to select either MasterTable1 or MasterTable2 or MasterTable3…

Instead of hardcoding the table name for the database query that populates the SELECT list, I attempted to implement a basic Ajax action (used example from w3schools)…and that’s when I lost my sanity…

I can output <div id='txtHint'></div> in my page and it shows the correct table name that was picked.

But how do I pass the correct table name to my query that will populate my SELECT list???

I tried 

 <select name="DBFilename" id="DBFilename" size="0"> 
 <option value="">Select Filename</option> 
<?php 
$sql="select distinct filename from "."<div id='txtHint'></div>";
$result = mysql_query($sql);
 while ($row = mysql_fetch_array($result)){ ?>  
 <option value="<?php echo $row['filename']; ?>"><?php echo $row['filename']; ?></option> 
 <?php } ?> 
 </select>

But to no avail. This is confusing since I can do this…

...
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","gettable.php?q="+str,true);
xmlhttp.send();
}
</script></head>
<body><form><select name="SrcTbl" id="SrcTbl" size="0" onchange="showTable(this.value)"> 
    <option value="">Select Data Table</option> 
    <option value=""> </option> 
<option value="MasterTable1">up to 31 days old</option> 
<option value="MasterTable2">62 days old</option> 
</select>
</form><br /><div id="txtHint"><select name="tabList"><option></option></select> </div>
</body></html>

And the name of my table will be displayed in the SELECT list ‘tablist’.

How do I pass the correct table name to my query that will populate my SELECT list? Thanks!!

(Pastebin =>form code)

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1 Answer

  1. Editorial Team

    m8, ajax is mainly used for user experience and populating a select list is so easy mode that it shouldnt be bothered with ajax in the first place!

    You should use ajax if you want to use some methods on user submitted data and create an illusion of seamless data exchange between the server and the client, and based on the return results render a corresponding view or an element of the view.

    unless you load every element of the view with ajax, you should populate your html with php from the start!

    <select name="DBFilename" id="DBFilename" size="whatever since style belongs to css"> 
<option selected="selected">Select Filename</option> 
<?php 
$sql="SELECT DISTINCT filename from 'wherever'";
$result = mysql_query($sql);
while ($row = mysql_fetch_array($result)){ ?>  
<option value="<?php echo $row['filename']; ?>"><?php echo $row['filename'];?>
</option> 
<?php } ?> 
</select>
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