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Home/ Questions/Q 6718335
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:57:25+00:00 2026-05-26T08:57:25+00:00

<div id=home> <div id=logo> </div> <div id=foot> <div class=button> CLICK ME</div> <div class=button two>

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<div id="home">
    <div id="logo">  </div>

        <div id="foot"> <div class="button"> CLICK ME</div>  
            <div class="button two"> CLICK ME</div> </div>
</div>

<div id="show">
    TEST TEST TEST TEST
</div>

$('.button').click(function(){
    $('#show').show();
})

#home {
 width: 400px;
 height: 400px;
 background-color: #ccffff;   
}

#logo {
   width: 100%;
   height: 300px;
    background-color: #0099ff;
}

#foot {
   width: 100%;
   height: 100px;
    background-color: #009999;
}

.button {
 width: 90px;
 height: 30px;
 background-color: red;
 margin-left: 50px;
}

i would like if i click RED .button then GREEN .show show me over the red button and if i click outside GREEN .show then this hide.

LIVE: http://jsfiddle.net/YeE4p/1/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:57:26+00:00Added an answer on May 26, 2026 at 8:57 am

    Is this somewhat close to what you are looking for?
    http://jsfiddle.net/neilheinrich/YeE4p/6/

    I had to change the #show div to be absolutely positioned and use this javascript:

    $('.button').click(function(){
    
      var $show = $('#show');
      var position = $(this).offset()
    
      $show.css({
        "left": position.left + "px", 
        "top":position.top + "px"
      }).show();
    
      $(window).bind("mousedown", function(e){
        if (!($(e.target).attr("id") === "show")) {
          $("#show").hide();
          $(window).unbind("mousedown");
        }
      });
    })
    
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