Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3781848
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 19, 20262026-05-19T10:59:58+00:00 2026-05-19T10:59:58+00:00

Django 1.2 is consistently giving me this CSRF verification error when I perform a

  • 0

Django 1.2 is consistently giving me this CSRF verification error when I perform a POST form. I “think” I’ve done all the things asked in the Django 1.2 docs, namely,

  1. Ensure MIDDLEWARE_CLASSES is included with ‘django.middleware.csrf.CsrfViewMiddleware’

  2. Ensure the {% csrf_token %}

    <form action="/words/new/" method="post">
    {% csrf_token %}
    {{ form.as_p }}
        <input type="submit" value="Enter" />
    </form>
    
  3. Use RequestContext in my response

    def create(request):
        if request.method == 'POST':
            form = DefinitionForm(request.POST)
            if form.is_valid():
                form.save()
            c = {}
            return render_to_response('dict/thanks.html',c, 
                                        context_instance=RequestContext(request))
        else:
            form = DefinitionForm()
        return render_to_response('dict/create_definition.html', {
            'form' : form,
        })
    

Note that the GET action works in this function. So I think I’m using render_to_response right.

I’ve even tried to throw in the @csrf_protect decorator and even that didn’t seem to work. I’m out of ideas and I’m about to choke myself with my laptop.

Any thing you guys can think of?

Thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-19T10:59:59+00:00Added an answer on May 19, 2026 at 10:59 am

    You’re not following #3. The RequestContext must be used with the rendering of the template that shows the form. It’s not necessary for the thanks page.

    return render_to_response('dict/create_definition.html', {
        'form' : form,
    }, context_instance=RequestContext(request))
    

    And as a side note, you should use the PRG pattern instead of rendering the thanks page directly.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Django comes with CSRF protection middleware , which generates a unique per-session token for
In Django 1.0, what is the best way to catch and show an error
I have custom exceptions in my django project that look like this: class CustomFooError(Exception):
I have 3 django models (simplified for this example): class Fighter (models.Model): name =
Django view points to a function, which can be a problem if you want
(Django 1.x, Python 2.6.x) I have models to the tune of: class Animal(models.Model): pass
In Django's template language, you can use {% url [viewname] [args] %} to generate
Does Django have any template tags to generate common HTML markup? For example, I
Using Django's built in models, how would one create a triple-join between three models.
My Django app has a Person table, which contains the following text in a

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.