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Home/ Questions/Q 1074225
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:05:37+00:00 2026-05-16T21:05:37+00:00

Django’s ORM (version 1.2.3) does not preserve identity when following foreign keys back and

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Django’s ORM (version 1.2.3) does not preserve identity when following foreign keys back and forth. This is best explained with an example:

class Parent(models.Model):
    pass

class Child(models.Model):
    parent = models.ForeignKey(Parent)

parent = Parents.objects.get(id=1)
for child in parent.child_set.all():
    print id(child.parent), "=!", id(parent)

So, for each child the parent is re-fetched from the database, even though we know the parent at the moment we fetch the child. This is counterintuitive to me.

In my case this also leads to performance issues, since I do some heavy operations at the parent level which I’d like to cache at object instance level. However, since the results of these calculations are accessed via the child => parent link, this caching at the parent level is useless.

Any ideas on how to solve this?

I’ve gotten as far as figuring out there’s a ForeignRelatedObjectsDescriptor and a ReverseSingleRelatedObjectDescriptor.

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:05:39+00:00Added an answer on May 16, 2026 at 9:05 pm

    There are a number of possible solutions to this.

    Perhaps the easiest is to keep track of the parent yourself:

    parent = Parents.objects.get(id=1)
    for child in parent.child_set.all():
        child._parent_cache = parent
    

    _FOO_cache is the way Django keeps track of items fetched via ForeignKey, so if you pre-populate that object on the child with the parent you already have, Django won’t fetch it again when you reference child.parent.

    Alternatively, you could look into one of the third-party libraries that attempt to fix this – django-idmapper or django-selectreverse are two I know of.

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