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Home/ Questions/Q 8949549
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T13:14:40+00:00 2026-06-15T13:14:40+00:00

<!DOCTYPE HTML> <html> <head> <meta http-equiv=Content-Type content=text/html; charset=utf-8> <title>NOVA</title> </head> <body> <form method=post action=file.com/>

  • 0
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>NOVA</title>
</head>
<body>
<form method="post" action="file.com/">
<table>
  <tr>
    <td>dataType</td>
    <td><input type="text" name="dataType" value="xml"></td>
  </tr>
  <tr>
    <td>actionType</td>
    <td><input type="text" name="actionType" value="query"></td>
  </tr>
  <tr>
    <td>accountid</td>
    <td><input type="text" name="accountid" value="121758"></td>
  </tr>
  <tr>
    <td>checksum</td>
    <td><input type="text" name="file" value="123"></td>
  </tr>
  <tr>
    <td></td>
    <td style="text-align:right"><input type="submit" value="send"></td>
  </tr>
</table>
</form>
</body>
</html>

This is what I’ve tried.

string xml = @"<Array><dataType>xml</dataType><actionType>query</actionType><accountid>121758</accountid><file>" + "123" + "</file></Array>";
WebRequest req = null;
WebResponse rsp = null;

string uri = "https://file.com/";
req = WebRequest.Create(uri);
req.Method = "POST";
req.ContentType = "text/xml";
StreamWriter writer = new StreamWriter(req.GetRequestStream());
writer.WriteLine(xml);
writer.Close();
rsp = req.GetResponse();

but this is not the same. I want exactly the same as form.submit();

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T13:14:41+00:00Added an answer on June 15, 2026 at 1:14 pm

    You’re code is more complicated than needed. It’s also incorrect. For example, the ContentType should be multipart/form-data, not text/xml.

    Instead, use a WebClient in conjunction with a NameValueCollection:

    using(WebClient client = new WebClient()) {
        NameValueCollection formValues = new NameValueCollection();
        formValues.Add("dataType", "xml");
        client.UploadValues("http://www.somesite.com/SomePage.aspx", formValues);
    }
    

    If you need to capture the response as well, use this method:

    byte[] response = null;
    
    using(WebClient client = new WebClient()) {
        NameValueCollection formValues = new NameValueCollection();
        formValues.Add("dataType", "xml");
        response = client.UploadValues("http://www.somesite.com/SomePage.aspx", formValues);
    }
    
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