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Home/ Questions/Q 88863
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Asked: May 10, 20262026-05-10T22:37:36+00:00 2026-05-10T22:37:36+00:00

$(document).ready(function() { $(span.link).mouseover(function(e){ $(this.children).css(display,inline); }); }); I’m not a javascript expert, but I’ve cobbled

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$(document).ready(function() {     $('span.link').mouseover(function(e){         $(this.children).css('display','inline');         });   });             

I’m not a javascript expert, but I’ve cobbled together a few functions using jQuery.

In this case, the stylesheet hides some controls. When the user mouses over, this function exposes those controls.

This works on every browser but Firefox (on the Mac and Windows). Am I missing something obvious?

Thanks for your help,

Jason

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  1. 2026-05-10T22:37:36+00:00Added an answer on May 10, 2026 at 10:37 pm

    Try it like this:

    $(function() {     $('span.link').mouseover(function(e){         $(this).children().css('display','inline');       }); }); 
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