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Home/ Questions/Q 3627370
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T23:52:47+00:00 2026-05-18T23:52:47+00:00

Documentation for logging module says that If you are implementing asynchronous signal handlers using

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Documentation for logging module says that

If you are implementing asynchronous signal handlers using the signal module, you may not be able to use logging from within such handlers. This is because lock implementations in the threading module are not always re-entrant, and so cannot be invoked from such signal handlers.

This suggests that one should not make logging calls from the code invoked by the signal handler directly or indirectly. If you do once in a while program will be left is a state when only kill -9 helps.

Important question for me now is following. Can this locking problem also happen when other threads call logging methods at the time when main thread is processing a signal?

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  1. Editorial Team
    Editorial Team
    2026-05-18T23:52:48+00:00Added an answer on May 18, 2026 at 11:52 pm

    Signal handlers need special handling in UNIX programming at all. Only a defined list of POSIX C functions are declared as reentrant and can be called within a POSIX signal handler. IEEE Std 1003.1 lists 118 reentrant UNIX functions you find at https://www.opengroup.org/ (login required).

    But Python signals are asynchronous: The signal module have an clarification:

    Although Python signal handlers are
    called asynchronously as far as the
    Python user is concerned, they can
    only occur between the “atomic”
    instructions of the Python
    interpreter. This means that signals
    arriving during long calculations
    implemented purely in C (such as
    regular expression matches on large
    bodies of text) may be delayed for an
    arbitrary amount of time.

    In this case, signals in Python are postponed until the GIL is free.

    Back to your question. No, as long you use re-entrant functions within signal processing function. If logging is used in threads only, there will be no problems.

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