Does a && (b = 5/a) assign 5/a to b (for nonzero a)?
My friend says it doesn’t, but I’m confused why it wouldn’t.
Does a && (b = 5/a) assign 5/a to b (for nonzero a )?
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Does a && (b = 5/a) assign 5/a to b (for nonzero a)?
My friend says it doesn’t, but I’m confused why it wouldn’t.
Your friend is wrong. For nonzero
a, the statementa && (b = 5/a)will assign the value5/atob.If
a == 0, then the conditional will short circuit and the assignment will not occur.