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Home/ Questions/Q 6356211
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T22:55:16+00:00 2026-05-24T22:55:16+00:00

Does a C++ compiler automatically convert: MyObject object2 = object1; into MyObject object2( object1

  • 0

Does a C++ compiler automatically convert:

MyObject object2 = object1;

into

MyObject object2( object1 );

?

Or does it treat it like:

MyObject object2;
object2 = object1;

?

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  1. Editorial Team
    Editorial Team
    2026-05-24T22:55:17+00:00Added an answer on May 24, 2026 at 10:55 pm

    You can try this to see the exact behavior:

    #include <iostream>
    
    class MyObject {
    public:
        MyObject() {
            std::cout << "MyObject()" << std::endl;
        }
        MyObject(const MyObject& other) {
            std::cout << "MyObject(const MyObject& other)" << std::endl;
        }
        MyObject& operator=(const MyObject& other) {
            std::cout << "operator=(const MyObject& other)" << std::endl;
            return *this;
        }
    };
    
    int main() {
        MyObject object1;
        MyObject object2 = object1;
        MyObject object3(object1);
        MyObject object4;
        object4 = object1;
    }
    

    Outputs:

    MyObject()
    MyObject(const MyObject& other)
    MyObject(const MyObject& other)
    MyObject()
    operator=(const MyObject& other)
    

    Apart from that, I recommend reading What is The Rule of Three?

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