Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3433410
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T07:34:13+00:00 2026-05-18T07:34:13+00:00

Does any one know how can I write a SQL Server script to check

  • 0

Does any one know how can I write a SQL Server script to check whether table is contain duplicate phone number?

Example:

I have a table called customer with following data

name   telephone
alvin  0396521254
alan   0396521425
amy    0396521425

How can I write a script in SQL Server that can return those records with duplicate telephone number??

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-18T07:34:14+00:00Added an answer on May 18, 2026 at 7:34 am

    To see values with duplicates:

      SELECT c.telephone
        FROM CUSTOMER c
    GROUP BY c.telephone
      HAVING COUNT(*) > 1
    

    To see related records in the table for those duplicates:

    SELECT c.*
      FROM CUSTOMER c
      JOIN (SELECT c.telephone
              FROM CUSTOMER c
          GROUP BY c.telephone
            HAVING COUNT(*) > 1) x ON x.telephone = c.telephone
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Does any one know how can I convert a BSTR to an int in
Does any one know from where can I download source code for Cassini. I
Does any one know of a control that i can use with a ASP.Net
Does anyone know how I can check to see if a directory is writeable
I need to check If a column value (string) in SQL server table starts
does anyone know a way to write a Doctrine migration to change the Table
Does anybody know of a proc or script which will generate any row into
Does anyone know how I can, in platform-independent C++ code prevent an object from
Does anyone know how I can achieve the following effect in OpenGL: Change the
Does anyone know how I can get rid of the following assembler warning? Code

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.