Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6001895
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T00:54:00+00:00 2026-05-23T00:54:00+00:00

Does anyone know how can I perform COUNT(*) on a query like this? SELECT

  • 0

Does anyone know how can I perform COUNT(*) on a query like this?

SELECT reviews.review_id, reviews.reviewers_rating, reviews.reviewers_name, reviews.review_date, reviews.pros, reviews.cons, products.product_name, products.slug, products.community_rating, products.number_of_votes, products.users_rating, products.thumb_link, categories.category_name_single
FROM reviews
LEFT JOIN products ON reviews.product_id = products.product_id
LEFT JOIN categories ON products.category = categories.category_id
WHERE reviews.approved =1
ORDER BY reviews.review_date DESC

Thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T00:54:01+00:00Added an answer on May 23, 2026 at 12:54 am

    Try this:

    SELECT Count(reviews.review_id), reviews.review_id, reviews.reviewers_rating, reviews.reviewers_name,  reviews.review_date, reviews.pros, reviews.cons, products.product_name, products.slug, products.community_rating, products.number_of_votes, products.users_rating, products.thumb_link, categories.category_name_single
    FROM reviews
    LEFT JOIN products ON reviews.product_id = products.product_id
    LEFT JOIN categories ON products.category = categories.category_id
    WHERE reviews.approved =1
    Group By reviews.review_id
    ORDER BY reviews.review_date DESC
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Does anyone know any good tool that I can use to perform stress tests
Does anyone know how can I cut a string and then assign into an
Does anyone know how can I detect the browser type in css? What I
Does anyone know where can I find recent data on PHP4 vs PHP5 market
Does anyone know how can I catch a mail error (error is displayed while
Does anyone know how can I edit a subitem on a listView? I've tried
I know I can use Request.Browser.IsMobileDevice . But does anyone know how it works,
Does anyone know how I can, in platform-independent C++ code prevent an object from
Does anyone know how I can check to see if a directory is writeable
Does anyone know how I can achieve the following effect in OpenGL: Change the

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.