Question

Does anyone know how I can use print to print out a file with a filename based on a variable?
At the moment if I do:

filename = 'pressure'; print -despc filename 

it saves the file as 'filename.eps'

Answer 1

like this:

print('-despc', filename) 

btw, switch -tiff can be useful to save tiff previews of an eps file.
to answer comment:

print('-despc', '-tiff', filename)    # saves eps file with tiff preview