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Home/ Questions/Q 6726469
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:55:52+00:00 2026-05-26T09:55:52+00:00

Does anyone know the bash construct where you specify the delimeter and you get

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Does anyone know the bash construct where you specify the delimeter and you get in two variables ( $@ or $! or something like that I think ) the values?

For example:
–option=false should be specified with ‘=’ delimeter and in one variable there will be the word ‘option’ whereas in the other variable the word ‘false’ is stored. Anyone know?

P.S.: No sed, awk or IFS solutions please. I am aware of them but I am requesting the specific bash construct 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:55:53+00:00Added an answer on May 26, 2026 at 9:55 am

    As found in the Bash man page, you can use Parameter Expansion to solve your problems.

    # split first argument on equal sign (left=right)    
    left=${1%%=*}
    right=${1#*=}
    
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