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Home/ Questions/Q 8430173
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T05:32:11+00:00 2026-06-10T05:32:11+00:00

Does anyone know where is my code going wrong here? This piece of code

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Does anyone know where is my code going wrong here? This piece of code work perfectly fine but I transferred the file to another computer, this error popped out when I compile the file.

 private void ShowGeneratedSchedule(string sLocationName, string sAllocationDate)
    {
        //lstAllocation = db.allocations.Where(a => a.AllocationDate == sAllocationDate &&
        //    a.LocationName == sLocationName).ToList();

        scheduleDGV.EditMode = DataGridViewEditMode.EditProgrammatically;
        for (int i = 0; i < lstAllocation.Count; i++)
        {
            for (int j = 0; j < scheduleDGV.Rows.Count - 1; j++)
            {
                for (int k = 0; k < scheduleDGV.Columns.Count; k++)
                {
                    if (scheduleDGV[0, j].Value.Equals(lstAllocation[i].LocationName) &&
                        scheduleDGV[1, j].Value.Equals(lstAllocation[i].StationName) &&
                        scheduleDGV.Columns[k].HeaderText.Equals(lstAllocation[i].AllocationTime.ToString()))
                    {
                        if (lstAllocation[i].EmployeeName != null)
                        {
                            scheduleDGV[k, j].Value = lstAllocation[i].EmployeeName;
                        }
                    }
                }
            }
        }

        //scheduleDGV.DataSource = lstEmployeeSlot;
    }

The error is displayed when it reaches this line,

for (int i = 0; i < lstAllocation.Count; i++)

Does anyone know what’s wrong here? Is it possible that it is transferred into another computer?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T05:32:13+00:00Added an answer on June 10, 2026 at 5:32 am

    lstAllocation is not initialized? What is it with the comment in the first line of the method? Why is that commented out? Without that lstAllocation has no content.

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