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Home/ Questions/Q 495229
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:34:24+00:00 2026-05-13T05:34:24+00:00

Does not work as expected becuase it does not set the MSB bit correct.

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Does not work as expected becuase it does not set the MSB bit correct.
I am using metrowerks compiler.

//shifting right 5 characters
char * buffer;
buffer=global_buffer;
for(i=0;i<5;i++) //shift right for 1;
{
    buffer[17-i]=(buffer[17-i]>>1)|(buffer[17-i-1]<<7);
}

EDIT
input buffer (just before for loop)
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x30,0x2F,0xA0,0xC6,0x9D

i got after for loop
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x17,0xD0,0xE3,0xCE

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:34:25+00:00Added an answer on May 13, 2026 at 5:34 am

    You probably want “unsigned char *buffer;” This will shift zeros into the top bits rather than retaining the sign bit.

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