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Home/ Questions/Q 6367297
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T00:31:50+00:00 2026-05-25T00:31:50+00:00

does not work echo ${REV%%\n*} does work echo ${REV%% *} After reading trough http://tldp.org/LDP/abs/html/parameter-substitution.html

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does not work

echo ${REV%%\n*}

does work

echo ${REV%%
*}

After reading trough http://tldp.org/LDP/abs/html/parameter-substitution.html I still can not figure out how to make \n work.

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  1. Editorial Team
    Editorial Team
    2026-05-25T00:31:51+00:00Added an answer on May 25, 2026 at 12:31 am

    ${REV%%$'\n*'} seems to work. See the quoting section of the bash documentation.

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