Question

Does the style of the formatter in the parse method of the DateTime class have to match the exact style of the string? For instance, I’m getting a TimeStamp object from the database (Oracle) and converting it to a string. In the database the TimeStamp is stored like this

08-AUG-12 12.00.00.000000000 AM

I set my formatter to this style

String pattern = "dd-MMM-yy";

I get this exception

java.lang.IllegalArgumentException: Invalid format: "08-AUG-12 12.00.00 AM" is malformed at " 12.00.00 AM"

org.joda.time.format.DateTimeFormatter.parseDateTime(DateTimeFormatter.java:866)

org.joda.time.DateTime.parse(DateTime.java:144)

What exactly does this mean and how would I go about fixing it? When I set my formatter to "yy-MMM-dd hh.mm.ss aa" I don’t get an exception but it prints in the browser like this: 2008-08-12T00:00:00.000-04:00, but I need for it to print out as "dd-MMM-yy hh:mm:ss aa"

Answer 1

Use LocalDateTime instead:

String input = "08-AUG-12 12.00.00 AM";
String pattern = "dd-MMM-yy hh.mm.ss aa";

LocalDateTime localDateTime = LocalDateTime.parse(input, DateTimeFormat.forPattern(pattern));

EDIT

As a matter of fact you can do it with DateTime also:

private static String parseDateTime(String input){
     String pattern = "dd-MMM-yy hh.mm.ss aa";
     DateTime dateTime  = DateTime.parse(input, DateTimeFormat.forPattern(pattern));
     return dateTime.toString("dd-MMM-yy hh:mm:ss aa");
}