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Does this result in undefined behaviour because the order of evaluation will be unspecified?
int i = 0, j = 0, k = 0;
int result = i++ + ++j + k++;
No, the result of the evaluation doesn’t depend on the unspecified order of evaluation of the sub-expressions.
Undefined behavior only occurs in this situation if two side effects that affect the same object are unsequenced relative to each other or a side effect and a value computation of the same object are unsequenced. The side-effect and value computation of both prefix and postfix increment are explicitly sequenced.