Question

double? test = true ? null : 1.0;

In my book, this is the same as

if (true) {
  test = null;
} else {
  test = 1.0;
}

But the first line gives this compiler error:

Type of conditional expression cannot
be determined because there is no
implicit conversion between ‘<null>‘
and ‘double‘.

Answer 1

This happens because the compiler tries to evaluate the statement from right to left.
This means that it sees 1.0 and it decides it is double (not double?) and then it sees null.

So there is clearly no implicit conversion between double and null (in fact there is no implicit conversion between Struct and null).

What you can do is explicitly tell the compiler that one of the two expressions that are convertible to each other.

double? test = true ? null : (double?) 1.0;    // 1
double? test = true ? (double?)null : 1.0;     // 2
double? test = true ?  default(double?) : 1.0; // 3
double? test = true ? new double?() : 1.0;     // 4