Question

DROP FUNCTION IF EXISTS shorten;
delimiter $$
CREATE FUNCTION shorten(s VARCHAR(255), n INT)
   RETURNS VARCHAR(255)
 BEGIN
 IF ISNULL(s) THEN
   RETURN '';
 ELSE IF n<15 THEN
    RETURN LEFT(s, n);
 ELSE IF CHAR_LENGTH(s) <= n THEN
   RETURN s;
 ELSE
  RETURN CONCAT(LEFT(s, n-10), ' ... ', RIGHT(s, 5));
  END IF;
 END$$

The message that I get is:

#1064 – You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ” at line 14
>

Where is teh error..cause I am new to making function in mysql.

UPDATE :

It points to an error with some rounded question mark between those lines:

ELSE IF n <15 THEN RETURN LEFT( s, n ) ;

ELSE IF CHAR_LENGTH( s ) <= n THEN RETURN s;

BTW, I use phpmyadmin

mysql version is: mysqlnd 5.0.10

Answer 1

I am not sure bt i don’t understand why you close if (END IF;) two times..?
This may be a probable problem in your code. Please check it.And ELSE IF should be without space i.e ELSEIF.
The code should be:

DROP FUNCTION IF EXISTS shorten;
delimiter $$
CREATE FUNCTION shorten(s VARCHAR(255), n INT)
RETURNS VARCHAR(255)
 BEGIN
 IF ISNULL(s) THEN
 RETURN '';
 ELSEIF n<15 THEN
RETURN LEFT(s, n);
 ELSEIF CHAR_LENGTH(s) <= n THEN
 RETURN s;
 ELSE
 RETURN CONCAT(LEFT(s, n-10), ' ... ', RIGHT(s, 5));
  END IF;
 END;$$
 delimiter;