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Home/ Questions/Q 4024812
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:46:05+00:00 2026-05-20T10:46:05+00:00

Due to Umbraco documentation being very…. how should I say.. ‘loose’? and split between

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Due to Umbraco documentation being very…. how should I say.. ‘loose’? and split between ‘old Umbraco’ and ‘current Umbraco’, I am finding it difficult to find a page that comprehensibly lists all of the standard/default fields of a Node/Document.

I am interested in the current version (4.6.1 at time of writing, using the ‘new schema’).

Fields such as:

  • updateDate
  • nodeName
  • level

So, what default/standard fields does every Umbraco Node/Document have?

EDIT:
OK, so it looks like that is the best answers we’re going to get. So using the xslt snippet posted by forzagaribaldi, we have the following list:

  • id
  • isdoc
  • path
  • creatorname
  • writername
  • urlname
  • nodename
  • updatedate
  • createdate
  • sortorder
  • template
  • nodetype
  • creatorid
  • writerid
  • level
  • parentid

(Case is wrong for all of these however, e.g. isdoc rather than isDoc)

If anyone can elaborate on this list they will get the tick!

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:46:06+00:00Added an answer on May 20, 2026 at 10:46 am

    You can always get an xml dump of a node by using xslt ‘copy-of’:

    <xsl:param name="currentPage"/>
    <xsl:template match="/">
     <xsl:copy-of select="$currentPage" />
    </xsl:template>
    

    Will return all elements and attributes (including nodename, createdate, updatedate, level, etc).

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