Question

Duplicate of the following question: C function conflict

---

Hi, in my current project I have to use some kind of interface lib. The function names are given by this interface, what this functions do is developers choice. As far as I can tell a project shall use this functions and when it comes to compiling you choose the lib and with it the functionality. What I try to do is to use an existing lib and my lib at the same time by wrapping the other and call it in mein functions:

otherlib:

int function1 (int a) { // do something } 

mylib:

int function1 (int a) { //my code here     otherlib::function1(a); } 

Problem is I don’t have access to the other lib and the other lib doesn’t have any namespaces. I already tried

namespace old {     #include 'otherlib.h' } 

and then call the old function by old::function1 in my function. This works as long as it’s only header file. The lib exports it’s symbol back into global space. Also something like

namespace new {     function1 (int a) {         ::function1(a);     } } 

didn’t work. Last but not least I tried ifdefs and defines suggested here

but I wasn’t successful.

Any ideas how to solve this? Thanks in advance.

EDIT: I neither have access to the old lib nor the project both libs shall be used in.

EDIT2: at least the old lib is a static one

Answer 1

Namespaces in C solved using library names prefixes like:

libfoo –> foo_function1
libbar –> bar_function1

These prefixes are actual namespaces. so if you write libbar

int bar_function1(int a) {      function1(a); } 

This is the way to solve problems.

C has namespaces — they just called prefixes 😉

Another option is to do various dirty tricks with dynamic loading of libraries like:

h1=dlopen('libfoo.so') foo_function1=dlsym(h1,'function1')  h2=dlopen('libbar.so') bar_function1=dlsym(h2,'function1')