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Asked: May 11, 20262026-05-11T06:45:38+00:00 2026-05-11T06:45:38+00:00

Duplicate. See this . Can someone tell me why this does not compile under

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Duplicate. See this.

Can someone tell me why this does not compile under GCC? Both MSVC6, and VS2008 will compile it, with no warnings, even.

The code…

#include <iostream> #include <vector> #include <ctime> #include <cstdlib> using namespace std; template <typename T> T range(vector<T> &v) {    vector<T>::iterator i = v.begin(); 

Throws an error on the last line, expected ; before i.

Do I need to typedef?

Most of the compiling I do is with MSVC6, or VS2008. I don’t do a whole lot with GCC, so I’m a little in the dark.

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  1. 2026-05-11T06:45:38+00:00Added an answer on May 11, 2026 at 6:45 am

    The compiler does not know enough to parse vector::iterator as a type at that point. Use the typename keyword to give it a hint:

    typename vector<T>::iterator i = v.begin(); 
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