Question

During display of an image from database in the gridview control, the following error occurred: Parameter is not valid

The following code displays the image:

        var id = Convert.ToString(user_id);

        var category = (from data in db.Register1_db
                        where (data.User_ID == id)
                       select ( data.Student_Photo));

        int len = category.First().Length;
        // Output the binary data          
        // But first we need to strip out the OLE header          
        int OleHeaderLength = 78;
        int strippedImageLength = len - OleHeaderLength;
        byte[] imagdata = new byte[strippedImageLength];          
        Array.Copy(category.First().ToArray(), OleHeaderLength, imagdata, 0, strippedImageLength);          
        if ((imagdata) != null)          
        {              
            MemoryStream m = new MemoryStream(imagdata);

                //error occurred               
            System.Drawing.Image image = System.Drawing.Image.FromStream(m);              
            image.Save(context.Response.OutputStream, ImageFormat.Jpeg);          
        }

Answer 1

The better way to display image in a gridview is using Image handlers.
Check this