Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8921611
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T06:35:21+00:00 2026-06-15T06:35:21+00:00

e.g I have the original matrix (m) looks like this one 1 2 3

  • 0

e.g I have the original matrix (m) looks like this one

1 2
3 4

Then I use n = padarray(m,[oldMatrixRow,OldMatrixColumn]); I will have

x x x x x x
x x x x x x 
x x 1 2 x x 
x x 3 4 x x 
x x x x x x
x x x x x x

The point here is that I would want my new matrix look like this

1 2 1 2 1 2
3 4 3 4 3 4
1 2 1 2 1 2
3 4 3 4 3 4
1 2 1 2 1 2
3 4 3 4 3 4

Is there any smart way to do that ?

Thank you very much

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T06:35:22+00:00Added an answer on June 15, 2026 at 6:35 am

    You want repmat

    B = repmat(A,m,n)
    

    where A is the matrix you want to repeat, and m and n define the dimensions of how it is repeated

    In your case here, call your original matrix A and use

    B = repmat(A,3,3)
    

    to get your desired output

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

If I have the original transform matrix of a rectangular UIImageView and this image
EDIT2 Looks like I can't read properly, disregard this post, I will try to
I have this original formula from a medical research book: Log(e) (EFW) = (-4.564+(0.282*AC)-(0.00331*AC^2))*1000
Let's say I have some original text: here is some text that has a
I was reading about Indexes in databases. First, I have my original table. Then
[Original] I have a ListBox which has its ItemsSource (this is done in the
I have a php script which saves the original image, then resizes it -
I have a Numpy array that looks like >>> a array([[ 3. , 2.
I have a headered matrix and I would like to add the word genes
I have a large matrix from which I would like to gather a collection

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.