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Home/ Questions/Q 8236395
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T19:07:17+00:00 2026-06-07T19:07:17+00:00

Each record in the collection has two key ip and timestamp db.posts.update({‘ip’ : ‘127.0.0.1’,

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Each record in the collection has two key “ip” and “timestamp”

db.posts.update({'ip' : '127.0.0.1', 'timestamp' : {'$gt' : sometimestamp}}, {'$set' : {'timestamp' : time.time()}, True)

The command above will insert a new record, if field “ip” with “127.0.0.1” not in the collection or “timestamp” is less than sometimestamp

Now, if I want to insert a new record only “ip” with “127.0.0.1” not in collection, in other word, keep value of “ip” unique.

How to do ?

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  1. Editorial Team
    Editorial Team
    2026-06-07T19:07:18+00:00Added an answer on June 7, 2026 at 7:07 pm

    What you are probably trying to do is this:

    if( ip=127)
       if( ts > myts)
          update;
        else
          DO NOTHING;
    else
       insert;
    

    So essentially, you are having two different types of updates..One is going to acutally make a change in timestamp and other tells mongo to do nothing, i.e., not even make an insert.
    I am guessing this is not possible with an upsert. So better use simple updates as follows:

    db.posts.update ( { 'ip' : '127.0.0.1', 'timestamp' : { '$gt' : sometimestamp } } , { '$set' : { 'timestamp' : time.time() } , False)
    

    And I don’t know how you’d write it in Pymongo, but logically speaking, you do this:

    if (db.posts.find_one( { 'ip':'127.0.0.1'} ) != null):
        db.posts.update ( {'ip' : '127.0.0.1'}, { '$set' : {'timestamp' : time.time() } } )
    

    Unfortunately, I can’t comment on the performance..

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