Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9130333
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 17, 20262026-06-17T07:56:46+00:00 2026-06-17T07:56:46+00:00

Each sort algorithm will be the job, but it’s a OVERKILL. For input like:

  • 0

Each sort algorithm will be the job, but it’s a OVERKILL.

For input like:

aa
cc
aa
bb
dd
bb
cc

I just need something like:

aa
aa
cc
cc
bb
bb
dd

The order of each pattern is not required.

Is there such an algorithm for this kind of job?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-17T07:56:47+00:00Added an answer on June 17, 2026 at 7:56 am

    You simply want to use a hashtable here, or more abstractly an associative array. Iterate over the input, adding it to the hashtable with value (tag, if you prefer) of 1 if it hasn’t yet been seen, or incrementing the count by one if it already exists in the hashtable.

    The algorithm is thus O(n) in both time and space, which is as good as you could reasonably expect. I recommend some reading up on hashtables, as it is a highly useful data structure that appears in all sorts of places in algorithm and software design.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I need to write something that will take data that looks like this: B
i want to sort dictionary based upon value of each dictioanry item.but if i
If we have some m >0 and need to provide an algorithm to sort
I have a need to develop an algorithm that will take a set of
I've made a few Badge classes in Django, each containing some sort of description
I have a recursive function which does a sort of tree process where each
Each key in dictionary has list of MANY integers. I need to iterate through
I need some advice to chose a sorting algorithm to code for this problem.
I need to write a code in C# that will select a list of
I am attempting to implement the Bitonic-Sort algorithm. Parallel Bitonic Sort Algorithm for processor

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.