Question

echo $1 $2 $3 ' -> echo $1 $2 $3'
args=("$@")
echo ${args[0]} ${args[1]} ${args[2]} ' -> args=("$@"); echo ${args[0]} ${args[1]} ${args[2]}'
echo $@ ' -> echo $@'
echo Number of arguments passed: $# ' -> echo Number of arguments passed: $#' 

This is suppose to be the output

But I get this instead.

Jasons-MacBook-Pro:bash jasonkim$ bash arguments.sh 
 -> echo $1 $2 $3
 -> args=("$@"); echo ${args[0]} ${args[1]} ${args[2]}
 -> echo $@
Number of arguments passed: 0  -> echo Number of arguments passed: $#

Answer 1

The problem isn’t that you can’t, it’s that you didn’t.

bash arguments.sh Bash Scripting Tutorial