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Home/ Questions/Q 6133791
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T17:16:23+00:00 2026-05-23T17:16:23+00:00

echo <img src=.$file. > ; does not display image, while $file points to the

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echo "<img src=".$file." >" ; 

does not display image, while $file points to the correct image location C:\wamp\www\formulae\public\images\13.png

part of code reads as follows

$file = LIBPATH.DS.'images'.DS.$id.'.png' ;
if(file_exists($file)){
echo $file."</br>";
echo "<img src='".$file."' >" ;

}
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  1. Editorial Team
    Editorial Team
    2026-05-23T17:16:24+00:00Added an answer on May 23, 2026 at 5:16 pm
    <img src="<?php echo file_dir . '/' . $imageone; ?>" height="100" width="100"/>
    

    would help you

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