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Home/ Questions/Q 507941
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:51:22+00:00 2026-05-13T06:51:22+00:00

@echo off SET var1=Yes SET var2=No SET var3=Yes if %var1%==Yes echo Var1 set if

  • 0
@echo off
SET var1="Yes"
SET var2="No"
SET var3="Yes"
if %var1%=="Yes"
    echo Var1 set
if %var2%=="Yes"
    echo Var2 set
if %var3%=="Yes"
    echo Var3 set

If I run the above script I get the following error. Can anyone pls help?

The syntax of the command is
incorrect.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:51:22+00:00Added an answer on May 13, 2026 at 6:51 am

    The echo needs to either be at the end of the if statement:

    if %var1%=="Yes" echo Var1 set
    

    or of the following form:

    if %var1%=="Yes" (
        echo Var1 set
    )
    

    I tend to use the former for very simple conditionals and the latter for multi-command ones and primitive while statements:

    :while1
        if %var1%=="Yes" (
            :: Do something that potentially changes var1
            goto :while1
        )
    

    What your particular piece of code is doing is trying to execute the command if %var1%=="Yes" which is not valid in and of itself.

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